*QUESTION:*Five numbers to be added are entered in different columns in an excel sheet. While writing the formula to calculate their sum, a user enters the wrong formula three times. First, he multiplies the numbers in order by 1, 2, 3, 4 and 5 before adding to get the result 1, then he multiplies the numbers in order by 3, 3, 7, 8 and 10 before adding to get the result 4. Finally, he multiplies them in order by 3, 2, 5, 5 and 6 before adding to get the sum 8. What is their actual sum?

*OPTIONS*1) 2

2) 4

3) 5

4) Cannot be determined

*Solution*Let the numbers in order be a, b, c, d and e.

It is given that

a + 2b + 3c + 4d + 5e = 1 … (i)

3a + 3b + 7c + 8d + 10e = 4 … (ii)

3a + 2b + 5c + 5d + 6e = 8 … (iii)

Subtracting the equation (i) from (ii), we get

2a + b + 4c + 4d + 5e = 3 … (iv)

Subtracting equation (iv) from (iii), we get

a + b + c + d + e = 5

Thus, the actual value of the sum is 5.

Hence, option 3.

.

## 0 comments:

## Post a Comment