An Average is a measure that tells us information about a group of things rather than data about individuals.

Mean, median, and mode are all types of averages, although the mean is the most common type of average and usually refers to the arithmetic mean. There are other kinds of means that are more difficult.

The arithmetic mean is a simple type of average. Suppose you want to know what the numerical average is in your math class. Let’s say your grades so far are 80, 90, 92, and 78 on the four quizzes you have had. To find your quiz average, add up the four grades: 80 + 90 + 92 + 78 = 340

Then divide that answer by the number of grades that you started with, four: 340/4 = 85. So, your quiz average is 85. Whenever you want to find a mean, just add up all the numbers and divide by the number of numbers you started with.

But sometimes the arithmetic mean doesn’t give you all the information you want. Suppose you are looking for a job. You interview with a company that has ten employees, and the interviewer tells you that the average salary is Rs. 20000 per month. That’s a lot of money! But that’s not what you would be making.

For this particular company, you would make half of that. Each employee makes Rs.10000 per month, except for the owner, who makes Rs.110000 per month. Nine employees make Rs.10000, so adding those up is 9 x 10000 =90000. Then the owner makes Rs.110000, so the total is Rs.110000 + Rs.90000 = Rs.200000. Divide by the total number of employees, ten, and we have Rs.20000/10 = Rs.2000. Because the owner makes so much more than everyone else, her salary “pulls” the average up.

A better question to ask is, “What is the median salary?” The median is the number in the middle, when the numbers are listed in order. For example, suppose you wanted to find the median of the numbers 6, 4, 67, 23, 6, 98, 8, 16, 37. First, list them in order: 4, 6, 6, 8, 16, 23, 37, 67, 98. Now, which one is in the middle? Well, there are nine numbers, so the middle one is the fifth, which is 16, so 16 is the median.

Now, what about when there is an even number of numbers? Look at the quiz grade example again: 90, 80, 92, 78. First list the numbers in order: 78, 80, 90, 92. The two middle ones are 80 and 90. So do we have two medians? No, we find the mean of those two: 80 + 90 = 170, and 170/2 = 85. So 85 is the median.

Now look at those salaries again. To find the median salary, we look at the salaries in order: 10000, 10000, 10000, 10000, 10000, 10000, 10000, 10000, 10000, 110000. This is an even number of salaries, so we look at the middle two. They are both 10000, so the median is Rs.10000. That’s much better at telling you how much you’ll make if you accept the job.

But the median doesn’t always give you the best information either. Suppose you interview with a company that has 10 general employees, 7 assistants, 3 managers, and 1 owner. For this company, the mean salary could be Rs.5000, and the median Rs. 4000. But you are applying for the position of general employee, whose starting salary is Rs. 1000.

The mode is the type of average you want to know in this situation. The mode is the number that occurs most frequently. In the example for median, 6 would be the mode because it occurs twice, while the other numbers each occur once. In our employee example, the mode is Rs. 10000 because that number occurs ten times, which is more than the number of times any other number occurs.

The most common value found in a group consisting of several readings is called as the ‘mode’. A group of observation can have more than one modal value.

± Mean, median and mode are all good types of averages, and each works best in different types of situations.

In the following example, we will measure the central tendency (that is mean; median, and mode values) of the given group of readings; and later we also will try to understand how these measures of central tendency may change when we add more values to the group of readings.

Example:

A person wrote down the time he spent on the exercises in a week. These readings are as follows.

Day Exercise time

Monday 20 min.

Tuesday 30 min.

Wednesday 20 min.

Thursday 35 min.

Friday 25 min.

The graph of the data is as shown below.

GRAPH

1. FNow we calculate the mean.

Mean = Sum of the readings/Number of readings = 20 + 30 +20 +35 +25/5

Therefore Mean = 130/5 = 26 minutes

Now we calculate the median, after arranging the given set of numbers in the increasing order we get,

Exercise time: 20, 20, 25, 30, and 35

The median (middle) value is 25 minutes.

Now we calculate the modal value. To calculate the mode we need to see how many times each number is repeating. And then the mode is the number that is repeating for the maximum.

Number 20 is repeating 2 times. Numbers 25, 30 and 35 are repeating only once. Therefore the mode is 20 minutes.

• ± the mean, median and mode must have the same unit that is associated with the given set of readings.

Let’s say the person adds Saturday in the exercise schedule. And on Saturday 30 minutes are spent on the exercise. To calculate the new mean value, add up all the readings and divide the sum by total number of readings.

Mean = 20 + 30 +20 +35 +20 + 30/6 = 160/6 = 26.66 minutes

Or, what we can do is multiply the original mean by the original number of readings to get the sum of the original readings.

26 x 5 = 130

We add the new value of 30 to this to get 160 and divide it by 6 to get the new mean. To calculate the new median, we rearrange the numbers in the increasing order. Therefore we now get,

Exercise time: 20, 20, 25, 30, 30, and 35

However in this case we do not have one single middle value. Instead we have two numbers in the middle that are 25 and 30. In this case we take the average of the two middle numbers to find the median. Therefore average of 25 and 30 is (25+30)/2 = 27.5 minutes.

Therefore the new median value is 27.5 minutes.

To calculate the new mode, we observe that numbers 20 and 30 minutes repeat 2 times. Numbers 25 and 35 minutes repeat only once. Therefore this set of readings has two mode values and the two modes are 20 and 30 minutes.

Example: Find the measures of central tendency for the following readings.

-2, 350%, 12, (-3)2, -80%

Solution: To compute the mean, median, or mode all the readings must be presented in the same number form.

Therefore we will need to convert the percentages into decimal form.

Therefore after converting the given set of readings into same number form, the new set has the following values.

-2, 3.5, 12, 9, -0.8

Now, mean = -2 + 3.5 +12 +9 − 0.8/5 = 21.7/5 = 4.34

Now median of the readings is the middle value of the set after arranging the numbers in the increasing order, which is

-2, -0.8, 3.5, 9, 12

Since none of the numbers repeats more than once, the above set of readings has no mode.

The concept of averages can be applied to problems in slightly different way.

Example: During the week, John watches TV every night after he finishes his homework. The following table shows how much time he spent last week watching television.

Day Entertainment time

Monday 1 hour

Tuesday 30 min.

Wednesday 30 min.

Thursday 45 min.

Friday 2 hours

John decided to include his TV time for Saturday and Sunday as well. When he did and recalculated his mean, mode and median he discovered that only the mean had changed. What can we say about the TV time for Saturday and Sunday that would produce this situation?

Solution: To proceed with the numbers, they must be converted to the same units. After rearranging the numbers to get the increasing order for entertainment time, we have: 30 min, 30 min, 45min, 60min, 120 min

Therefore, mean = 285/5 = 57 min and median = 45 min.

Since number 30 repeats 2 times and other numbers repeat only once, we can say that mode = 30 min.

We need to find additional possible values for Saturday and Sunday that will not change the median and mode.

Let us look at the number sequence.

30, 30, 45, 60, 120

If 45 should remain as the median (in the middle), then if we write a number to its left, we must write a number to its right side also. And if number 30 should remain as the mode, then the two more numbers, representing Saturday and Sunday, that we will include into to the data set must be different from 45, 60 and 120.

Therefore we can say if 45 minutes should remain the median value for the entire week, then if John spends more than 45 minutes but neither 1 hour nor 2 hours watching TV on Saturday, then on Sunday he must spend less than 45 minutes watching television. (The amount of time spent on TV on Saturday and Sunday can be swapped).

Average properties

1. If each number in a set of data points is increased by a certain number x, then the average will be increase by x, similarly for incase of decrease it will decrease by x, and in case of multiplication it will be multiplied by x.

Example: In a class of ten students, where the average weight is 50 kgs, if weight of each student is increased by 5 kg what will be the new average?

Number of students = 10, average = 50,

Total weight of class = 500 (50 × 10)

In case each student’s weight is increased by 5 kg, excess weight = 50 (5 × 10)

Total weight of the class will become = 500 + 50 = 550

Average weight = = 55, so average is also increased by 5 kgs

2. The average speed in case of a journey from X to Y at speed of A m/sec and returning back to X at a speed of B m/sec, is m/sec

Example: Sunil travels from Delhi to Noida at the speed of 40 km/hr and returns at the speed of 50 km/hr. What is the average speed of the journey?

Using the formula,

=

= = 44.44 Km/hr

Always remember the units, in what units you have started and in what units you are ending.

Alternative way is by the basic principle of mechanics,

Speed =

Which means Time =

And Average Speed =

Suppose distance from Delhi to Noida is A, therefore

Time while going, T1 =

Time while coming T2 =

Total time = =

Total Distance = A + A = 2A

Average speed = =

=

=

= 44.44 Km/hr

Here are some concepts of various kinds of mean, students are requested to go through the concepts and understand the applications rather that cramming the formulas. There is no direct question expected in CAT on basis of these formulas, But application may be used widely in many concepts especially data interpretation.

Arithmetic mean: As the definition given above, The AM of n numbers X1, X2, X3 …… Xn is denoted by X and calculated as

X =

X =

The S is called sigma, which represents summation, from values 1 to n.

For many values it is difficult to calculate mean using this formula. There is an easier formula for that using two concepts, Assumed mean (a) and Deviation (d) from the Assumed mean

X =

Here di = Xi – a

Example: AM of 20, 30, 40, 52, 96, 34, 36. Let the assumed mean be 40

Xi di

20 20 – 40 = – 20

30 30 – 40 = – 10

40 40 – 40 = 0

52 52 – 40 = 12

96 96 – 40 = 56

34 34 – 40 = – 6

36 36 – 40 = – 4

S di = 28

Mean, X = 40 + = 40 + = 40 + 4 = 44

Weighted AM: If there are two values, a and b, have weights (or frequency) of x and y, then the weighted arithmetic mean is given by

WAM =

What is “weight” in weighted mean?

The weight is the relative strength of a data point, lets take respective an example:

Strength: Suppose there is a paper with four sections of 100 marks each – Maths, English, Social studies and History. Now there are different weightages assigned to each that is Maths – 40%, English – 20%, Social studies – 20% and History – 20%. If a student gets following marks (Maths –60, English – 60, Social studies – 50 and History – 50) in different subjects, what are the net marks out of 100?

Here to get net marks out of 100, the respective marks in subjects have to be treated with its weights as per following table:

Subject Marks Net marks

(marks*weight)

Maths 60 0.4(40%) 24

English 60 0.2(20%) 12

Social studies 50 0.2(20%) 10

History 50 0.2(20%) 10

Total (out of 100) – Mean Marks 56

Let’s also understand what is frequency?

Frequency: The concept of frequency is not the same as weight but can be treated in the same manner. Suppose the marks in English for a class of 10 people are 50, 60, 50, 51, 65, 60, 50, 36, 60 and 65. Here 50 have occurred 3 times, 60 has occurred three times etc, so the times a data point occurs in a set of data points is called its frequency. Now for the above give data points, the following is the frequency and mean calculation:

Marks Frequency Total

50 3 150

60 3 180

51 1 51

65 2 130

36 1 36

Total 10 547

So the mean here is = 54.7

If Weights W1, W2 …..Wn are assigned to the values X1, X2 ….. Xn, then the Weighted AM

WAM =

Example: WAM of 10, 15, 20, 25 with frequency 1, 2, 3, 5

Xi Wi Wi Xi

10 1 10

15 2 30

20 3 60

25 5 125

10 225

S Wi = 10 S Xi Wi = 225

WAM = = 22.5

Mean of means: If the means (M1, M2...) are given along with numbers (N1, N2...), then the mean of means is given by using the Weighted Arithmetic Mean formula, where weights are replaced by respective number:

Mean of means =

Example: The mean marks scored by 60 boys are 80 and those scored by 100 girls are 60

Mean = = = 67.5 Marks

Geometric mean: The other mean is the geometric mean, which is given by nth root of the product of n numbers.

GM of A1 , A2 , A3 , ... An =

Example: GM of 2 and 8 is = = 4

Properties

1. The AM of given set of data points is always equal to or greater than their GM, that is AM =GM

Example: Find the Geometric mean and Arithmetic mean of 2, 8

Arithmetic Mean = = 5

Geometric Mean = = = 4

2. If the geometric mean of one group of “a” numbers is x and that of another group of “b” numbers is y, then the geometric mean of the combined groups is:

Harmonic mean: The Harmonic mean is give by

For two numbers a and b Harmonic mean is given by

HM =

= =

For N numbers (a, b, c … n),

HM =

Harmonic mean is used to calculate average speed, with different speeds for same distance.

Example: Ajay travels from Delhi to Shimla at the speed of 50 km/hr and returns at the speed of 40 km/hr, what is the average speed of the journey?

Using the formula of Harmonic Mean,

=

= = 44.44 Km/hr

Weighted Harmonic Mean: The Weighted Harmonic mean is give by

For two numbers a and b with weights x and y it is given by

Weighted HM =

This is used to calculate the average speed when different distances are covered at different speeds.

Example: A man covers his first 6 km at an average speed of 10 m/s, another 4 km at 8 m/s and the last 3 km at 5 m/s.

Average speed = weighted HM =

Mode: It is the number that occurs most frequently in a given set of numbers.

Example: In set of numbers, 1, 2, 3, 4, 5, 5, 4, 3, 2, 1 and 5, the number 5 occurred the maximum number of times, so the mode is 5.

Median: It is the middle value of a set of data points arranged in an ascending or descending order.

If the number of data points is odd, the median is value.

If the number of data points is even, the median is give by the average of the two middle values, suppose the medium values are a and b, here median is given by .

Here

a = and b = + 1

Example: Median of numbers 25, 22, 30, 29, 36

First the values need to be arranged in the ascending order 22, 25, 29, 30, 36

Median is the value Þ 3rd value, which is 30

Example: Median of numbers 25, 22, 30, 29, 36, 38

First the values need to be arranged in the ascending order 22, 25, 29, 30, 36, 38

The two middle values are = 3 and + 1 = 4, the 3rd and 4th values are 29 and 30

Thus median = = = 28.

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